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In the adjoining figure, ∠MNP = 90°, seg NQ ⊥ seg MP, MQ = 9, QP = 4, find NQ. |
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Answer» In ∆MNP, ∠MNP = 90° and [Given] seg NQ ⊥ seg MP NQ2 = MQ × QP [Theorem of geometric mean] ∴ NQ = \(\sqrt{MQ \times QP}\) [Taking square root of both sides] \(=\sqrt{9 \times 4}\) \(=3 \times 2\) ∴ NQ = 6 units |
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