1.

In the adjoining figure, ∠MNP = 90°, seg NQ ⊥ seg MP, MQ = 9, QP = 4, find NQ.

Answer»

In ∆MNP, ∠MNP = 90° and [Given] 

seg NQ ⊥ seg MP

NQ2 = MQ × QP [Theorem of geometric mean]

∴ NQ = \(\sqrt{MQ \times QP}\) [Taking square root of both sides]

\(=\sqrt{9 \times 4}\)

\(=3 \times 2\)

∴ NQ = 6 units



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