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In the adjoining figure, ∠MNP = 90° , seg NQ ⊥ seg MP,MQ = 9, QP = 4, find NQ. |
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Answer» In ∆MNP, ∠MNP = 90° and [Given] seg NQ ⊥ seg MP NQ2 = MQ × QP [Theorem of geometric mean] ∴ NQ = \({ \ \sqrt{MQ\times QP} }\) [Taking square root of both sides] = \({ \ \sqrt{9\times 4} }\)= 3 × 2 ∴NQ = 6 units |
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