1.

In the adjoining figure, ∠MNP = 90° , seg NQ ⊥ seg MP,MQ = 9, QP = 4, find NQ.

Answer»

In ∆MNP, ∠MNP = 90° and [Given] 

seg NQ ⊥ seg MP 

NQ2 = MQ × QP [Theorem of geometric mean] 

∴ NQ = \({ \ \sqrt{MQ\times QP} }\) [Taking square root of both sides] 

= \({ \ \sqrt{9\times 4} }\)= 3 × 2 

∴NQ = 6 units



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