In the adjoining figure, ∠QPR = 90°, seg PM ⊥ seg QR and Q – M – InterviewSolution

InterviewSolution

1.

In the adjoining figure, ∠QPR = 90°, seg PM ⊥ seg QR and Q – M – R, PM = 10, QM = 8, find QR.

Answer»

In ∆PQR, ∠QPR = 90° and [Given]

seg PM ⊥ seg QR

∴ PM² = OM × MR [Theorem of geometric mean]

∴ 10² = 8 × MR

∴ MR = \(\frac{100}{8}\)

= 12.5

Now, QR = QM + MR [Q – M – R]

= 8 + 12.5

∴ QR = 20.5 units

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