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In the circuit given below, the capacitor is initially having a charge of 10 C.1 second after the switch is closed, the current in the circuit is ________(a) 14.7 A(b) 18.5 A(c) 40.0 A(d) 50.0 AI have been asked this question in an online interview.Asked question is from Advanced Problems Involving Complex Circuit Diagram in division Network Theory and Complex Circuit Diagram of Network Theory

Answer»

Right choice is (a) 14.7 A

Explanation: Using KVL, 100 = \(R\frac{dq}{DT} + \frac{Q}{C}\)

100 C = \(RC\frac{dq}{dt}\) + q

Or, \(\int_{q_o}^q \frac{dq}{100C-q} = \frac{1}{RC} ∫_0^t \,dt\)

100C – q = (100C – qo)e^-t/RC

I = \(\frac{dq}{dt} = \frac{(100C – q_o)}{RC} e^{-1/1}\)

∴ e^-t/RC = 40e^-1 = 14.7 A.



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