In the circuit given below, the phase angle of the current I with respect to the voltage V1 is __________(a) 0°(b) +45°(c) -45°(d) -90°The question was asked in an interview.I want to ask this question from Advanced Problems Involving Complex Circuit Diagram in division Network Theory and Complex Circuit Diagram of Network Theory

In the circuit given below, the phase angle of the current I with resp

1.	In the circuit given below, the phase angle of the current I with respect to the voltage V1 is __________(a) 0°(b) +45°(c) -45°(d) -90°The question was asked in an interview.I want to ask this question from Advanced Problems Involving Complex Circuit Diagram in division Network Theory and Complex Circuit Diagram of Network Theory
Answer» Right answer is (d) -90° For explanation: NET VOLTAGE applied to the circuit is 200∠0° V I1 = \(\frac{200∠0°}{10.0}\) = 20∠0° = 20 I2 = \(\frac{200∠0°}{10∠90°}\) = 20∠-90° = -j20 I = I1 + I2 = 20(1-j) = 20\(\SQRT{2}\)∠45° Voltage V1 = 100(1+j) = 100\(\sqrt{2}\)∠45° ∴ Required phase angle = -45° – 45° = -90°.

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