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In the circuit given below, the value of IX using nodal analysis is _______(a) -2.5 A(b) 2.5 A(c) 5 A(d) -5 AThe question was posed to me in a job interview.I want to ask this question from Advanced Problems on Network Theory in chapter Network Theory and Complex Circuit Diagram of Network Theory

Answer»

Right option is (B) 2.5 A

Easiest explanation: Applying KCL, we get, I1 + 5 = I2 + I3

∴ \(\FRAC{10 – V_1}{1} + 5 = \frac{V_1}{2} + \frac{V_2}{6}\)

30 – 3V1 + 15 = 3V1 + V2

∴ 6 V1 + V2 = 45

From voltage source, V2 – V1 = 10

Now, 7 V1 = 35, V1 = 5 V

And V2 = 15 V

∴ IX = \(\frac{V_2}{6} = \frac{15}{6}\) = 2.5 A.



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