InterviewSolution
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InterviewSolution
| 1. |
In the figure DE||OQ and DF||OR show that EF||QR |
| Answer» In {tex}\\triangle PQO{/tex}\xa0{tex}\\because DE||OQ{/tex}{tex}\\therefore \\frac{{PD}}{{DO}} = \\frac{{PE}}{{EQ}}{/tex}\xa0....... (1) [By basic proportionality theorem]In {tex}\\triangle PRO\\,\\because DF||OR{/tex}{tex}\\therefore \\frac{{PD}}{{DO}} = \\frac{{PF}}{{FR}}{/tex}....... (2) [By basic proportionality theorem]from (1) and (2),\xa0{tex}\\frac{{PE}}{{EQ}} = \\frac{{PF}}{{FR}}{/tex}{tex}\\therefore {/tex}\xa0{tex}EF||QR{/tex}\xa0...... [By converse of basic proportionality theorem] | |