Saved Bookmarks
| 1. |
In the figure given find ‹QSR |
| Answer» Given: PQ and PR are tangents to a circle with centre O and {tex}\\angle{/tex}QPR = 50°.To find: {tex}\\angle{/tex}QSR{tex}\\angle{/tex}QOR + {tex}\\angle{/tex}{tex}QPR = 180°{/tex}{tex}\\Rightarrow{/tex}\xa0{tex}\\angle{/tex}{tex}QOR + 50° = 180°{/tex}{tex}\\Rightarrow{/tex}\xa0{tex}\\angle{/tex}{tex}QOR = 130°{/tex}{tex}\\Rightarrow{/tex}\xa0{tex}\\angle{/tex}QSR = {tex}\\frac {1} {2}{/tex}\xa0{tex}\\angle{/tex}QOR{tex}\\Rightarrow{/tex}\xa0{tex}\\angle{/tex}QSR = {tex}\\frac {1} {2}{/tex}\xa0{tex}\\times{/tex}\xa0{tex}130° = 65°{/tex} | |