InterviewSolution
Saved Bookmarks
| 1. |
in the given figure ^a=90°, ^b=90° ob=4.5cm oa=6cm & ad=4cm find qb |
| Answer» In {tex}\\triangle{/tex}PAO and {tex}\\triangle{/tex}QBO{tex}\\angle{/tex}A = {tex}\\angle{/tex}B = 90o{tex}\\angle{/tex}POA = {tex}\\angle{/tex}QOB (Vertically Opposite Angle){tex}\\triangle{/tex}PAO ~ {tex}\\triangle{/tex}QBO,(by AA criteria){tex}\\frac { O A } { O B } = \\frac { P A } { Q B }{/tex}or,\xa0{tex}\\frac { 6 } { 4.5 } = \\frac { 4 } { Q B }{/tex}or,\xa0{tex}Q B = \\frac { 4 \\times 4.5 } { 6 }{/tex}Therefore, QB = 3 cm | |