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| 1. |
in the given figure De parallel to OQ and DE parallel to OR prove that EF parallel to OQ |
| Answer» In {tex}\\triangle {/tex}OQP,DE || OQ{tex}\\frac{{PE}}{{EQ}} = \\frac{{PD}}{{DO}}{/tex} .....(i)In {tex}\\triangle {/tex}OPR,DF {tex} \\bot {/tex} OR{tex}\\frac{{PD}}{{DO}} = \\frac{{PF}}{{FR}}{/tex} .....(ii)From (i) and (ii) , we get{tex}\\frac{{PE}}{{EQ}} = \\frac{{PF}}{{FR}}{/tex}{tex}\\therefore {/tex} From {tex}\\triangle {/tex}PQREF {tex} \\bot {/tex} OR | |