In the given figure if DE parallel BC then calculate x

1.	In the given figure if DE parallel BC then calculate x
Answer» In the given figure,DE \u200b{tex}\\parallel {/tex}\u200b BC\u200b{tex}\\therefore {/tex}\u200b {tex}\\frac{{AD}}{{DB}} = \\frac{{AE}}{{EC}}{/tex}\u200b{tex}\\Rightarrow {/tex}\u200b {tex}\\frac{x}{{x - 2}} = \\frac{{x + 2}}{{x - 1}}{/tex}\u200b{tex}\\Rightarrow {/tex}\u200b x = 4\xa0

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