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In the given question, two equations numbered l and II are given. Solve both the equations andmark the appropriate answer.I.7x2 + 32x – 15 = 0II. 4y2– 16y +7 = 01. x > y2. x < y3. x ≤ y4. x ≥ y5. x = y or the relationship between x and y cannot be established. |
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Answer» Correct Answer - Option 2 : x < y Calculation: From I, 7x2 + 32x – 15 = 0 ⇒ 7x2 + 35x – 3x – 15x = 0 ⇒ 7x(x+5) – 3(x+5) = 0 ⇒ (7x–3) (x+5) = 0 Taking, ⇒ 7x – 3 = 0 or x + 5 = 0 ⇒ x = 3/7 or –5 From II, 4y2– 16y + 7 = 0 ⇒ 4y2– 14y - 2y + 7 = 0 ⇒ 2y(2y–1) –7(2y-1) = 0 ⇒ (2y–1) (2y–7) = 0 Taking, ⇒ 2y – 1 = 0 or 2y – 7 = 0 ⇒ y = 1/2 or y = 7/2
∴ Relation between x and y is, x < y. |
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