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In the given question, two equations numbered l and II are given. Solve both the equations and mark the appropriate answer.I. x2 + 9x + 14 = 0II. 3y2 + 4y + 1 = 01. x > y2. x < y3. x ≥ y4. x ≤ y5. x = y or relationship between x and y can't be established |
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Answer» Correct Answer - Option 2 : x < y I. x2 + 9x + 14 = 0 ⇒ x2 + 7x + 2x + 14 = 0 ⇒ x (x + 7) + 2 (x + 7) = 0 ⇒ (x + 2)(x + 7) = 0 ⇒ x = - 2, -7 II. 3y2 + 4y + 1 = 0 ⇒ 3y2 + 3y + y + 1 = 0 ⇒ 3y(y + 1) + 1(y + 1) = 0 ⇒ (3y + 1)(y + 1) = 0 ⇒ \(y = - 1, - \frac{1}{3}\) On comparing the values of x and y,
∴ x < y |
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