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In the given question, two equations numbered l and II are given. Solve both the equations and mark the appropriate answer.I. 5x2 - 14x -3 = 0II. 9y2 + 16y - 4 = 01. y ≤ x2. y ≥ x3. y > x4. y < x5. x = y 0r no relation cannot be established |
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Answer» Correct Answer - Option 5 : x = y 0r no relation cannot be established I. 5x2 - 14x -3 = 0 ⇒ 5x2 -15x + x - 3 =0 ⇒ 5x( x - 3) + 1(x -3) = 0 ⇒ (5x +1)(x -3) = 0 ⇒ x = -1/5, 3 II. 9y2 + 16y - 4 = 0 ⇒ 9y2 -18y + 2y - 4 =0 ⇒ 9y( y - 2) + 2(y -2) = 0 ⇒ (9y + 2)(y - 2) = 0 ⇒ y = -2/9, 2
∴ No relation can established between x,y |
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