1.

In the given question, two equations numbered l and II are given. Solve both the equations and mark the appropriate answer.I. 5x2 - 14x -3 = 0II. 9y2 + 16y - 4 = 01. y ≤ x2. y ≥ x3. y > x4. y < x5. x = y 0r no relation cannot be established

Answer» Correct Answer - Option 5 : x = y 0r no relation cannot be established

I. 5x2 - 14x -3 = 0

⇒ 5x2 -15x + x - 3 =0

⇒ 5x( x - 3) + 1(x -3) = 0 

⇒ (5x +1)(x -3) = 0

⇒ x = -1/5, 3

II. 9y2 + 16y - 4 = 0

⇒ 9y2 -18y + 2y - 4 =0

⇒ 9y( y - 2) + 2(y -2) = 0 

⇒ (9y + 2)(y - 2) = 0

⇒ y = -2/9, 2

 

value of xvalue of yrelation x,y
  -1/5  -2/9 x > y
  3 2 x > y
 -1/5 2 x< y
  3 -2/9 x > y

 

∴ No relation can established between x,y



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