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In the given question, two equations numbered l and II are given. You have to solve both the equations and mark the appropriate answer-I. 2x2 + 6x – 80 = 0II. 3y2 + 12y + 9 = 01. x > y2. x ≥ y 3. x < y4. x ≤ y5. x = y or the relation cannot be established |
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Answer» Correct Answer - Option 5 : x = y or the relation cannot be established Equation I: 2x2 + 6x – 80 = 0 ⇒ 2x2 – 10x + 16x – 80 = 0 ⇒ (2x + 16) (x – 5) = 0 ⇒ x = - 8 or x = 5 Equation II: 3y2 + 12y + 9 = 0 ⇒ 3y2 + 3y + 9y + 9 = 0 ⇒ (3y + 9) (y + 1) = 0 ⇒ y = - 3 or y = - 1 Comparing the values of x and y, x = y or the relation cannot be established |
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