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In the given question, two equations numbered l and II are given. Solve both the equations and mark the appropriate answer.I. 3x2 + 19x + 20 = 0II. 6y2 + 19y +15 = 01. x ˃ y2. x ˂ y3. x ≥ y4. x ≤ y5. x = y or the relationship between x and y cannot be established. |
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Answer» Correct Answer - Option 5 : x = y or the relationship between x and y cannot be established. From equation I) we get, 3x2 + 19x + 20 = 0 ⇒ 3x2 + 15x+ 4x + 20 = 0 ⇒ 3x (x+ 5) + 4(x+5) + 20 = 0 ⇒ (x+5) (3x + 4) = 0 ∴ x = -5, - 4/3 From equation II) we get, 6y2 + 19y + 15 = 0 ⇒ 6y2 + 10y + 9y + 15 = 0 ⇒ 2y (3y + 5) + 3(3y + 5) = 0 ⇒ (2y + 3) (3y + 5) = 0 ∴ y = -3/2, -5/3 Comparison between x and y (via Tabulation):
∴ The relationship between x and y cannot be established. |
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