1.

In the given question, two equations numbered l and II are given. Solve both the equations and mark the appropriate answer.l. x2 – 3x – 4 = 0ll. y2 – 5y – 6 = 01. x > y2. x < y3. x ≥ y4. x ≤ y5. x = y OR relation between x and y can not be established.

Answer» Correct Answer - Option 5 : x = y OR relation between x and y can not be established.

Calculation:

l. x2 – 3x – 4 = 0

⇒ x2 – 4x + x – 4 = 0

⇒ x(x – 4) + 1(x – 4) = 0

⇒ (x – 4) (x + 1) = 0

⇒ x = 4, -1.

ll. y2 – 5y – 6 = 0

⇒ y2 – 6y + y – 6 = 0

⇒ y(y – 6) + 1(y – 6) = 0

⇒ (y + 1) (y – 6) = 0

⇒ y = 6, -1.

Comparison between x and y (via Tabulation):

Value of x

Value of y

Relation

4

6

x < y

4

-1

x > y

-1

6

x < y

-1

-1

x = y


∴ The relation between x and y can not be established.


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