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In the given questions, two equations numbered I and II are given. You have to solve both the equations and mark the appropriate answer.I. x2 + 3√ 3 x - 120 = 0II 6y2 + 13√ 3y + 20  =01. x ≥ y2. x > y3. x ≤ y4. x < y5. No relation or x = y

Answer» Correct Answer - Option 5 : No relation or x = y

I. x2 + 3√ 3 x - 120 = 0

⇒ x2 + 8√3x - 5√ 3x - 120 = 0

⇒ x (x + 8√ 3x) - 5√ 3(x + 8√ 3) = 0

⇒ (x - 5√ 3)(x + 8√ 3 ) = 0

⇒ x = 5√ 3, -8√ 3

II 6y2 + 13√ 3y + 20  = 0

⇒ 6y2 + 8√3x + 5√ 3x +20 = 0

⇒2√3 y (√ 3 y + 4) - 5(√ y + 4) = 0

⇒ (2√ 3 y - 5)(√ 3 y + 4 ) = 0

⇒ y = -5//2√ 3, -4/√ 3

value of xvalue of yrelation x,y
5√ 35//2√ 3x > y
5√ 3-4/√ 3x > y
-8√ 35//2√ 3x < y
-8√ 3-4/√ 3x < y

 

∴ There is no relation between x and y


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