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In the given questions, two equations numbered I and II are given. You have to solve both the equations and mark the appropriate answer.I.2y2 - 13y -34 =0II. 7x2 + 25x + 12 =01. x ≥ y2. x ≤ y3. x < y4. x > y5. No relation or x = y |
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Answer» Correct Answer - Option 3 : x < y I.2y2 - 13y - 34 =0 ⇒ 2y2 + 4y - 17y - 34 = 0 ⇒ 2y(y + 2) - 17 ( y + 2) = 0 ⇒ (2y - 17) ( y + 2) = 0 ⇒ y = 17/2, -2 II. 7x2 + 25x + 12 =0 ⇒ 7x2 + 21x + 4x + 12 = 0 ⇒ 7x ( x + 3) + 4 ( x+ 3) = 0 ⇒ (7x + 4) (x + 3) = 0 ⇒ x = -4/3, -3
∴ x < y
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