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In the roots of quadratic equation of 6x2-6-2=0 |
| Answer» 6x2- x - 2 = 0or, 6x2 + 3x - 4x - 2 = 0or, 3x(2x + 1) -2(2x + 1) = 0or, (2x + 1)(3x - 2) = 0{tex}\\Rightarrow{/tex} either 3x - 2 = 0 or 2x + 1 = 0{tex}\\therefore \\quad x = \\frac { 2 } { 3 } \\text { or } x = - \\frac { 1 } { 2 }{/tex}Therefore, Roots of equation are\xa0{tex}\\frac { 2 } { 3 } \\text { and } - \\frac { 1 } { 2 }{/tex}. | |