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| 1. |
In traingle pqr right angle atq PQ=3 and PR=6 determine angle QPR and angle PRQ |
| Answer» ∆PQR is a right angle triangleby Pythagoras theorem(PR)^2=(PQ)^2+(QR)^26^2=3^2+((QR)^236=9+(QR)^236-9=(QR)^2(QR)^2=27QR=✓9×3QR=3✓2AngleQPR =60° because side opposite to P is ✓3/2 times the hypo(PR)Angle PRQ=30° because side opposite to R is 1/2 of the hypo(PR) | |