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In triangle abc ,ab=5,ac=13 ,find the value of tan A+cotC. |
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Answer» {tex}\\style{font-size:12px}{\\begin{array}{l}AB=5,AC=13\\\\\\mathrm{So}\\;\\mathrm{BC}^2=\\mathrm{AC}^2-\\mathrm{AB}^2\\\\=169-25=144\\\\\\mathrm{BC}=12\\\\\\mathrm{Now}\\;\\mathrm{tanA}+\\mathrm{cotC}\\\\=\\frac{\\mathrm{BC}}{\\mathrm{AB}}+\\frac{\\mathrm{AB}}{\\mathrm{BC}}\\\\=\\frac{12}5+\\frac5{12}=\\frac{144+25}{60}=\\frac{169}{60}\\end{array}}{/tex} Tan12\\5 COT12\\5 |
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