In triangle ABC, angle B = 90° , If sinA = 3/4 , then show that cosA + sinC = root 7 /2 ??

In triangle ABC, angle B = 90° , If sinA = 3/4 , then show that cosA

1.	In triangle ABC, angle B = 90° , If sinA = 3/4 , then show that cosA + sinC = root 7 /2 ??
Answer» Welcome Ok thanks for answering my question. Given that sinA=3/4=opp/hyp =3x/4xBy using Pythagoras theorem find adj of angle AU will get x root 7By using this information find sinC and cosA. U will get 2 root 7 / 4. If u simplify further u will get root 7 / 2