In triangle ABC DE parallel AB if AD=2x DC=x+3 BE=2x-1 and CE=x then find the value of x

In triangle ABC DE parallel AB if AD=2x DC=x+3 BE=2x-1 and CE=x then f

1.	In triangle ABC DE parallel AB if AD=2x DC=x+3 BE=2x-1 and CE=x then find the value of x
Answer» DC/AD=CE/BETherefore,x+3/2x= x/2x-1 (x+3)(2x-1)=(2x)(x)2x^2+6x-x-3=2x^25x-3=0. (Cancelling 2x^2)5x=3x=3/5