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in triangle ABC right angled at B,angle A =angleC find value of sinA cosC+cosA sinC\u200b |
| Answer» Answer:The value=1Step-by-step explanation:∠B=90°∠A=∠CHyp= ACOther sides= BC, ABsinA= BC/ACcosA=AB/ACsinC= AB/ACcosC= BC/ACUsing Pythagoras TheoremAC²=BC²+AB²sinA cosC+cosA sinC=BC/AC*BC/AC +AB/AC*BC/AC=BC²/AC² +AB²/AC²=AB²+BC/AC²=AC²/AC²=1 | |