In triangle ABC , write sin A+B/2in terms of angle C

1.	In triangle ABC , write sin A+B/2in terms of angle C
Answer» We know that in triangle ABCAngle (A + B + C) = 180Transfer angle on right side,Angle(A+B) = 180- Angle CDividing 2 on both side , we getAngle(A+B)/2 = 90 - Angle C/2Multiply sin on both sidesin A+B/2 = sin(90-C/2)sin A + B/2 = cos C/2

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