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In triangle OPQ, right angled at P, OP = 7cm and OQ - PQ =1cm. Determine the value of sinQ and cosQ. |
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Answer» Ha ncert ka h Given: OP=7cm, OQ-PQ =1 OQ = 1+ PQOQ^2 = OP^2 + QP^2(1 + PQ) = 7^2 + PQ^21 + 2PQ + PQ^2 = 49 + PQ^22PQ = 48PQ = 24OQ = 1+PQ = 1+ 24 = 25SinQ = OP÷OQ = 7÷25CosQ = QP÷OQ = 24 ÷ 25 Ncert ka h Ye question kis page me hai |
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