In triangle pqr angle q = 90 and sin r = 3/5 write the value of cos p

1.	In triangle pqr angle q = 90 and sin r = 3/5 write the value of cos p
Answer» Let pq=3x & pr=5x Cos p =adj/hypt. =3/5 R+P=90°=› P=90-R=› cosP=cos(90-R) = sinR = 3/5

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