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In triangle PQR ST perallel QR PS/SQ=3/5 and PR=28cm.find PT

Answer» given PS/SQ=3/5 SO PQ=3+5=8 ST parallel QR PT= in triangle PQR (by bpt corollary PQ/PS=PR/PT 8/3=28/PT PT=28×3÷8 PT=21/2


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