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In what ratio does the point (-4,6) divide the line segment joining the point A(-6,10)and B(3,-8)

Answer» Let (-4, 6) divide AB internally in the ratio k:1. Using the section formula, we get{tex}( - 4,6 ) = \\left( \\frac { 3 k - 6 } { k + 1 } , \\frac { - 8 k + 10 } { k + 1 } \\right){/tex}So,\xa0{tex}- 4 = \\frac { 3 k - 6 } { k + 1 }{/tex}i.e., -4k - 4 = 3k - 6i.e., 7k = 2i.e., k:1 = 2:7\xa0


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