1.

In what ratio the milk costing Rs. 24 per liter must be mixed with water to make mixture cost Rs. 18 per liter taking cost of pure water to be 0 ?1). 3 : 72). 2 : 33). 3 : 14). 1 : 3

Answer»

Let QUANTITY of milk = x liters

Price of pure milk = RS. 24/liter

∴ Cost of milk in mixture = 24x

Let quantity of water = y liters

Price of water = 0

Total mixture = x + y

Total cost of mixture = 24x + 0 = 24x

As per the question,

Total cost of mixture: 18 × (x + y)

∴ 24x = 18 × (x + y)

⇒ 24x = 18x + 18Y

⇒ 24x – 18x = 18y

⇒ 6x = 18y

$(\Rightarrow \;\FRAC{x}{y} = \;\frac{{18}}{6}\; \Rightarrow \;\frac{x}{y} = \;\frac{3}{1}\;)$

∴ Required RATIO = 3 ? 1


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