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In what ratio the milk costing Rs. 24 per liter must be mixed with water to make mixture cost Rs. 18 per liter taking cost of pure water to be 0 ?1). 3 : 72). 2 : 33). 3 : 14). 1 : 3 |
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Answer» Let QUANTITY of milk = x liters Price of pure milk = RS. 24/liter ∴ Cost of milk in mixture = 24x Let quantity of water = y liters Price of water = 0 Total mixture = x + y Total cost of mixture = 24x + 0 = 24x As per the question, Total cost of mixture: 18 × (x + y) ∴ 24x = 18 × (x + y) ⇒ 24x = 18x + 18Y ⇒ 24x – 18x = 18y ⇒ 6x = 18y $(\Rightarrow \;\FRAC{x}{y} = \;\frac{{18}}{6}\; \Rightarrow \;\frac{x}{y} = \;\frac{3}{1}\;)$ ∴ Required RATIO = 3 ? 1 |
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