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In YDSE, light of wavelength `5000 Å` is used. The third bright band on the screen is formed at a distance of `1 cm` from the central bright band. If the screen is at a distance of `1.5 m` from the centre of narrow slits, calculate the separation between the slits. |
Answer» Correct Answer - `2.25 xx 10^(-4) m` Here,`lambda = 5000 Å = 5 xx 10^(-7)m, n =3` `x_(3) = 1 cm = 10^(-2)m, D = 1.5m, d = ?` `x_(3) = n (lambda D)/(d)` `10^(-2) = 3 xx 510^(-7) xx (1.5)/(d) = (22.5 xx 10^(2))/(d)` `d = (22.5 xx 10^(-7))/(10^(-2)) = 22.5 xx 10^(-5)m` `= 2.25 xx 10^(-4)m` |
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