InterviewSolution
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InterviewSolution
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`int_(0)^(pi//2)e^(x)sinxdx` का मान हैA. `(1)/(2)(e^(pi//2)-1)`B. `(1)/(2)(e^(pi//2)+1)`C. `(1)/(2)(1-e^(pi//2))`D. `2(e^(pi//2)+1)` |
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Answer» Correct Answer - B `I=int_(0)^(pi//2)e^(x)sinxdx` `=[(e^(x))/(2)(sinx-cosx)]_(0)^(pi//2)` `[becauseinte^(ax)sinbxdx=(e^(ax))/(a^(2)+b^(2))(asinbx-bcosbx)]` `=[(e^(pi//2))/(2)(1-0)-(1)/(2)(0-1)]=(1)/(2)(e^(pi//2)+1)` |
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