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`int_(0)^(pi//4)sqrt(1+sin 2x)dx` का मान ज्ञात कीजिए । |
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Answer» `int_(0)^(pi//4)sqrt(1+sin2x)dx` `=int_(0)^(pi//4)sqrt(sin^(@)x+cos^(2)x+2sin x cosx)` `=int_(0)^(pi//4)sqrt((cosx+sinx)^(2))dx` `(because 1=cos^(2)x+sin^(2)x, sin 2x=2sin x cosx)` `=int_(0)^(pi//4)(cosx+sinx)dx=[sinx-cosx]_(0)^(pi//4)` `=(sin.(pi)/(4)-cos.(pi)/(4))-(sin0-cos0)` `=((1)/(sqrt2)-(1)/(sqrt2))-(0-1)=1` |
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