`int(3x^2)/(1+x^6)dx`A. `sin^(-1)x^(3)+C`B. `cos^(-1)x^(3)+C`C. `tan^(-1)x^(3)+C`D. `cot^(-1)x^(3)+C`

`int(3x^2)/(1+x^6)dx`A. `sin^(-1)x^(3)+C`B. `cos^(-1)x^(3)+C`C. `tan^(

1.	`int(3x^2)/(1+x^6)dx`A. `sin^(-1)x^(3)+C`B. `cos^(-1)x^(3)+C`C. `tan^(-1)x^(3)+C`D. `cot^(-1)x^(3)+C`
Answer» Correct Answer - C Putting `x^(3)=t and3x^(2)dx=dt`, we get : `I=int(dt)/((1+t^(2)))=tan^(-1)t+C=tan^(-1)x^(3)+C`.