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`int_(pi//4)^(pi//2)e^(x)(logsinx+cotx)dx` का मान हैA. `e^(pi//4)log2`B. `-e^(pi//4)log2`C. `(1)/(2)e^(pi//4)log2`D. `-(1)/(2)e^(pi//4)log2` |
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Answer» Correct Answer - D `I=int_(pi//4)^(pi//2)e^(x)(logsinx+cotx)dx` `=[e^(x)logsinx]_(pi//4)^(pi//2)-int_(pi//4)^(pi//2)cotx dx+int_(pi//4)^(pi//2)e^(x)cotxdx` `=[e^(x)logsinx]_(pi//4)^(pi//2)` `=[e^(pi//2)log1-e^(pi//4)logsqrt(2)]` `=-(1)/(2)e^(pi//4)log2` |
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