InterviewSolution
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InterviewSolution
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`int(sin(x-alpha))/(sin(x+alpha))dx=?`A. `xcos2alpha-sin2alpha*log|sin(x+alpha)|+C`B. `xcos2alpha+sin2alpha*log|sin(x+alpha)|+C`C. `xcos2alpha+sinalpha*log|sin(x+alpha)|+C`D. none of these |
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Answer» Correct Answer - A `(sin(x-alpha))/(sin(x+alpha))=(sin(x+alpha-2alpha))/(sin(x+alpha))=(sin(x+alpha)cos2alpha-cos(s+alpha)sin2alpha)/(sin(x+alpha))`. `=cos2alpha-sin2alphacot(x+alpha)` `:." "I=int{cos2alpha-sin2alpha*cot(x+alpha)}dx` `=(cos2alpha)*intdx-sin2alpha*intcot(x+alpha)dx`. `=cos2alpha-sin2alpha*log|sin(x+alpha)|+C`. |
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