`int(sin2x)/(1+bcosx)^(2)dx`

1.	`int(sin2x)/(1+bcosx)^(2)dx`
Answer» Correct Answer - `(-2)/(b^(2)){:[log\|a+bcosx\|+(a)/((a+bcosx))]:}+C` Put `(a+bcosx)=t."Then",cosx=((t-a))/(b)and-sin"x dx"=(1)/(b)dt`. `:.I=-(2)/(b)int(1)/(t^(2))((t-a)/(b))dt=-(2)/(b^(2))int{(1)/(t)-(a)/(t^(2))}dt`.

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