`int(x^2)/(9+4x^2)dx`

1.	`int(x^2)/(9+4x^2)dx`
Answer» Correct Answer - `(x)/(4)-(3)/(8)"tan"^(-1)((2x)/(3))+C` On dividing `x^(2)` by `(4x^(2)+9)`, we get ` (x^(2))/((9+4x^(2)))=(1)/(4)-((9//4))/(4x^(2)+9)`. `thereforeI=(1)/(4)dx-(9)/(19)*int(dx)/({x^(2)((3)/(2))^(2)})`.

Discussion

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