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`inte^(cos^(2))sin2xdx=?`A. `e^(cos^(2)x)+C`B. `-e^(cos^(2)x)+C`C. `e^(sin^(2)x)+C`D. none of these |
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Answer» Correct Answer - B Put `cos^(2)x=t and-2cosxsinxdx=dt`. `:." "I=-inte^(t)dt=-e^(t)+C=-e^(cos^(2))+C`. |
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