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`inte^(sinx)sin2x dx`A. `(2sinx)e^(sinx)+C`B. `(2cosx)e^(sinx)+C`C. `2e^(sinx)(sinx+1)+C`D. `2e^(sinx)(sinx-1)+C` |
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Answer» Correct Answer - D `I=2inte^(sinx)sinxcosxdx=2intunderset(I)(t)underset(II)e^(t)"dt, where "sinx=t`. |
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