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Integrate the functions`(2cosx-3sinx)/(6cosx+4sinx)`

Answer» `int(2cosx-3sinx)/(6cosx+9sinx) dx`let 6cosx+9sinx=t(2cosx-3sinx)dx=(dt)/2=`int1/t(dt)/2`=`1/2 log|t|+C`=`1/2 log |6 cosx+4sinx|+C`


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