1.

`intlog_10 x dx=`A. `(1)/(x)log_(e)10+C`B. `(1)/(x)log_(10)e+C`C. `x(logx-1)log_(e)10+C`D. `x(logx-1)log_(10)e+C`

Answer» Correct Answer - D
`I=int(logx)/(log10)dx=(1)/(log_(e)10)*underset(I)((logx))*underset(II)(1)dx=(log_(10)e)*int{underset(I)((logx))*underset(II)(1)}dx`


Discussion

No Comment Found