InterviewSolution
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`intlog_10 x dx=`A. `(1)/(x)log_(e)10+C`B. `(1)/(x)log_(10)e+C`C. `x(logx-1)log_(e)10+C`D. `x(logx-1)log_(10)e+C` |
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Answer» Correct Answer - D `I=int(logx)/(log10)dx=(1)/(log_(e)10)*underset(I)((logx))*underset(II)(1)dx=(log_(10)e)*int{underset(I)((logx))*underset(II)(1)}dx` |
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