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`intsec^-1xdx`A. `xsec^(-1)x+log|x+sqrt(x^(2)-1)|+C`B. `xsec^(-1)x-log|x+sqrt(x^(2)-1)|+C`C. `xsec^(-1)x+log|x-sqrt(x^(2)-1)|+C`D. none of these |
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Answer» Correct Answer - B Put `sec^(-1)x=t," so that "x=sect anddx=sect tantdt`. `:." "I=intunderset(I)(t)underset(II)((sect tant))dt`. |
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