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`intsec^(3)xdx=?`A. `(1)/(2){secxtanx-log|secx+tanx|}+C`B. `(1)/(2){secxtanx+log|secx+tanx|}+C`C. `2{secxtanx+log|secx+tanx|}+C`D. none of these |
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Answer» Correct Answer - B `I=intunderset(II)(sec^(2))x*underset(I)(sec)xdx=secxtanx-intsecxtan^(2)xdx` `=secxtanx-intsecx(sec^(2)x-1)dx=secxtanx-I+int+secxdx` `:." "2I=secxtanx+log|secx+tanx|+C`. |
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