1.

`intsec^(3)xdx=?`A. `(1)/(2){secxtanx-log|secx+tanx|}+C`B. `(1)/(2){secxtanx+log|secx+tanx|}+C`C. `2{secxtanx+log|secx+tanx|}+C`D. none of these

Answer» Correct Answer - B
`I=intunderset(II)(sec^(2))x*underset(I)(sec)xdx=secxtanx-intsecxtan^(2)xdx`
`=secxtanx-intsecx(sec^(2)x-1)dx=secxtanx-I+int+secxdx`
`:." "2I=secxtanx+log|secx+tanx|+C`.


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