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`inttan^5xdx`A. `(1)/(6)tan^(6)x+C`B. `(1)/(4)tan^(4)x+(1)/(2)tan^(2)x+log|secx|+C`C. `(1)/(4)tan^(4)x-(1)/(2)x+log|secx|+C`D. none of these |
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Answer» Correct Answer - C `I=inttan^(3)xtan^(2)xdx=inttan^(3)x(sec^(2)x-1)dx`. `=inttan^(3)xsec^(2)xdx-inttan^(3)xdx=intt^(3)dt-inttanx(sec^(2)x-1)dx`, where tan x=t `=(t^(4))/(4)-inttanxsec^(2)xdx+inttanxdx` `=(1)/(4)tan^(4)x-intudu+log|secx|+C`, where tan x=u `=(1)/(4)tan^(4)x-(1)/(2)u^(2)+log|secx|+C=(1)/(4)tan^(4)x-(1)/(2)tan^(2)x+log|secx|+C`. |
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