1.

`inttanxdx=?`A. `log|cosx|+C`B. `-log|cosx|+C`C. `log|sinx|+C`D. `-log|sinx|+C`

Answer» Correct Answer - B
`I=int(sinx)/(cosx)dx=int(-dt)/(t)`, where cos x=t.
`=-log|t|+C=-log|cosx|+C`.


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