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`intx^(2)cosxdx=?`A. `x^(2)sinx+2xcosx-2sinx+C`B. `2xcosx-xsinx+2sinx+C`C. `x^(2)sinx-2xsinx+2sinx+C`D. none of these |
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Answer» Correct Answer - A `I=intunderset(I)(x^(2))underset(II)(cos)xdx=x^(2)sinx-intunderset(I)(2x)underset(II)(sin)xdx` `=(x^(2)sinx)-2[x(-cosx)-int(-cosx)dx]+C` `=(x^(2)sinx)+2xcosx-2sinx+C`. |
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