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`intxsec^(2)xdx=?`A. `xtanx-log|cosx|+C`B. `xtanx+log|cosx|C`C. `xtanx+log|secx|+C`D. none of these |
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Answer» Correct Answer - B `intunderset(I)(x)underset(II)(sec^(2))xdx` |
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