It is given that the difference between the zeros of 4x^2-8kx+9 is 4 a

1.	It is given that the difference between the zeros of 4x^2-8kx+9 is 4 and k>0 then k = ?
Answer» Let, the two zeroes of the polynomial f(x) = 4x2 - 8kx - 9 be α and -α.Comparing f(x) = 4x2\xa0- 8kx - 9 with ax2+bx+c we geta = 4; b = -8k and c = -9.Sum of the zeroes = α + (-α) ={tex}-\\frac ba=\\;-\\frac{-8k}4 {/tex}0 = 2kk = 0

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